This would help any Sysad who wants to retain or keep the latest backups or files automatically using a script.
Sample Codes Below:
#!/bin/bash
#
# This script retains 2 files
# Created by Burnz Barbosa
#
#
LOG_FILE="/var/log/retain_script.log"
cd /mnt/backups/full
num_files=`ls | wc -l`
rm `ls -tp | grep -v "/$" | awk '{ if (NR > 2) print; }'`
num_files2=`ls | wc -l`
/bin/echo "[$(date)]You have the latest $num_files2 retained in backup files " >> $LOG_FILE
Script Explanations:
The script is to keep the latest 2 files under /mnt/backups/full
1. We declare the log file at /var/log/ named as retain_script.log
2. Go to the backup directory, lets assumed /mnt/backups/full
3. Then we remove the count of oldest files and retain the latest 2
4. We ask to display the counts or number of files that it contains
5. We write a log with a date telling how many backups have retained and put it in the logfile
Remarkable issues here. I am very happy to peer your article.
Thank you so much and I am taking a look forward to contact you.
Will you kindly drop me a mail?
Sure! Thank you so much!
Works like a charm. Thank you!
Everything is very open with a very clear
clarification of the challenges. It was definitely informative.
Your site is useful. Thank you for sharing!
Hi,
Thanks for the script. I wanted to know what does the $ sign does “grep -v “/$” ” ?
I know grep -v does invert match but just not able to understand $ part.
Any help would be appreciated.
Thanks,
Jimy
Hi Jimy,
That’s a good question!
To explain further:
grep – it print lines matching a pattern | -v – invert the sense of matching, to select non-matching lines (-v is specified by POSIX.) | “/$” – grep searches the named input FILEs (or standard input if no files are named, or if a single hyphen-minus (-) is given as file name) for lines containing a match to the given PATTERN. By default, grep prints the matching lines.
I hope i was able to answer your question. 🙂
Thank you!